Posts Tagged ‘I/O’

Monitoring ESX Storage Queues

July 30, 2013

6a00d8341c328153ef01774354e2fd970d-500wiQueue Limits

I/O data goes through several storage queues on its way to disk drives. VMware is responsible for VM queue, LUN queue and HBA queue. VM and LUN queues are usually equal to 32 operations. It means that each ESX host at any moment can have no more than 32 active operations to a LUN. Same is true for VMs. Each VM can have as many as 32 active operations to a datastore. And if multiple VMs share the same datastore, their combined I/O flow can’t go over the 32 operations limit (per LUN queue for QLogic HBAs has been increased from 32 to 64 operations in vSphere 5). HBA queue size is much bigger and can hold several thousand operations (4096 for QLogic, however I can see in my config that driver is configured with 1014 operations).

Queue Monitoring

You can monitor storage queues of ESX host from the console. Run “esxtop”, press “d” to view disk adapter stats, then press “f” to open fields selection and add Queue Stats by pressing “d”.

AQLEN column will show the queue depth of the storage adapter. CMDS/s is the real-time number of IOPS. DAVG is the latency which comes from the frame traversing through the “driver – HBA – fabric – array SP” path and should be less than 20ms. Otherwise it means that storage is not coping. KAVG shows the time which operation spent in hypervisor kernel queue and should be less than 2ms.

Press “u” to see disk device statistics. Press “f” to open the add or remove fields dialog and select Queue Stats “f”. Here you’ll see a number of active (ACTV) and queue (QUED) operations per LUN.  %USD is the queue load. If you’re hitting 100 in %USD and see operations under QUED column, then again it means that your storage cannot manage the load an you need to redistribute your workload between spindles.

Some useful documents:

Advertisements

Unexpected Deduplication Impact on VMware I/O Latency

May 28, 2013

NetApp deduplication is a postponed process. During normal operation Data ONTAP only calculates hashes for the data blocks. Actual deduplication is carried out off-hours as per configured schedule. Hash calculation doesn’t affect performance in most cases. I talked about that in my previous post. NetApp states in its documentation that deduplication is a low-priority process:

When one deduplication process is running, there is 0% to 15% performance degradation on other applications.

Once I faced a situation when deduplication was configured to be carried out during business hours on one of the volumes. No one noticed that at some point volume run out of space and Data ONTAP wasn’t able to perform deduplication from that time. Situation became worse when Data ONTAP was upgraded from version 7.3.2 to 8.1.0. Now during deduplication filer tried to upgrade the fingerprint metadata to a new version at 15:00 every day with the message: “Fingerprint is being upgraded” and failed. It seems that the metadata upgrade is a very resource-intensive process and heavily affects I/O latency.

This volume was not a VMware datastore, but it sit on the same aggregate together with the several VMFS LUNs. Here what happened to the VMware I/O latency every day at 15:00 (click to enlarge):

dedup_issue_ed

I deleted the host name and the datastores names from the graph. You can see the large latency spike, which won’t turn yourVMs into kernel panic, but it’s not the thing you would want your production environment to experience every day.

The solution was simple. After space was increased on this volume, deduplication metadata upgrade performed successfully and problem went away. Additionally, deduplication was shifted to off-hours.

The simple lesson to learn: don’t schedule deduplication during the day, you never know what could possibly go wrong.

Storwize V7000 with vSphere 5 storage configuration

December 1, 2012

storwizeInformation on how to configure Storwize for optimal performance is very scarce. I’ll try to build some understanding of it from bits an pieces gathered throughout the Internet and redbooks.

Barry Whyte gave many insights on Storwize internals in his blog. Particularly his “Configuring IBM Storwize V7000 and SVC for Optimal Performance” series of posts. I’ll quote him here. The main Storwize redbook “Implementing the IBM Storwize V7000 V6.3” is mostly an administration guide and gives no useful information on the topic. I find “SAN Volume Controller Best Practices and Performance Guidelines” way more helpful (Storwize firmware is built on SVC code).

Total Number of MDisks

That’s what Barry says:

… At the heart of each V7000 controller canister is an Intel Jasper Forrest (Sandy Bridge) based quad core CPU. … When we added the tried and trusted (SSA) DS8000 RAID functionality in 2010 (6.1.0) we therefore assigned RAID processing on a per mdisk basis to a single core. That means you need at least 4 arrays per V7000 to get maximal CPU core performance. …

Number of MDisks per Storage Pool

SVC Redbook:

The capability to stripe across disk arrays is the single most important performance advantage of the SVC; however, striping across more arrays is not necessarily better. The objective here is to only add as many arrays to a single Storage Pool as required to meet the performance objectives.

If the Storage Pool is already meeting its performance objectives, we recommend that, in most cases, you add the new MDisks to new Storage Pools rather than add the new MDisks to existing Storage Pools.

Table 5-1 shows the recommended number of arrays per Storage Pool that is appropriate for general cases.

Controller type       Arrays per Storage Pool
DS4000/DS5000         4 - 24
DS6000/DS8000         4 - 12
IBM Storwise V7000    4 - 12

The development recommendations for Storwize V7000 are summarized below:

  • One MDisk group per storage subsystem
  • One MDisk group per RAID array type (RAID 5 versus RAID 10)
  • One MDisk and MDisk group per disk type (10K versus 15K RPM, or 146 GB versus 300 GB)

There are situations where multiple MDisk groups are desirable:

  • Workload isolation
  • Short-stroking a production MDisk group
  • Managing different workloads in different groups

We recommend that you have at least two MDisk groups, one for key applications, another for everything else.

Number of LUNs per Storage Pool

SVC Redbook:

We generally recommend that you configure LUNs to use the entire array, which is especially true for midrange storage subsystems where multiple LUNs configured to an array have shown to result in a significant performance degradation. The performance degradation is attributed mainly to smaller cache sizes and the inefficient use of available cache, defeating the subsystem’s ability to perform “full stride writes” for Redundant Array of Independent Disks 5 (RAID 5) arrays. Additionally, I/O queues for multiple LUNs directed at the same array can have a tendency to overdrive the array.

Table 5-2 provides our recommended guidelines for array provisioning on IBM storage subsystems.

Controller type                     LUNs per array
IBM System Storage DS4000/DS5000    1
IBM System Storage DS6000/DS8000    1 - 2
IBM Storwize V7000                  1

General considerations

vsphere5-logoLets take a look at vSphere use case scenario on top of Storwize with 16 x 600GB SAS drives in control enclosure and 10 x 2TB NL-SAS in extension enclosure (our personal case).

First of all we need to decide how many arrays we need. Do we have different workloads? No. All storage will be assigned to virtual machines which have in general the same random read/write access pattern. Do we need to isolate workloads? Probably yes, it’s generally a good idea to separate highly critical production VMs from everything else. Do we have different drive types? Yes. Obviously we don’t want to mix drive types in one RAID. Are we going to make different RAID types? Again, yes. RAID 10 is appropriate on SAS and RAID 5 on NL-SAS. So two MDisks – one RAID 10 on SAS and one RAID 5 on NL-SAS would be enough. Storwize nodes have 4 cores each. It may seem that you would benefit from 4 MDisks, but in fact you won’t. Here what Barry says:

In the case where you only have 1 or 2 HDD arrays, then the core stuff doesn’t really come into play. Its only when you get to larger systems, where you are driving more I/O than a single RAID core can handle that you need to spread them.

This is also true if you are running all SSD arrays, so 24x SSD would be best split into 4 arrays to get maximum IOPs, whereas 24x HDD are not going to saturate a single core, so (if you could create a 23+P! [ you can’t 15+P is largest we support ] then it would perform as well as 2x 11+P etc

To storage pools. In our example we have two MDisks, so you simply make two storage pools. In future if you hit performance limit, you create additional MDisks and then you have two options. If each MDisk separately is able to sustain your performance requirements, you make additional storage pools and redistribute workload between them. If you have huge load on storage and even redistribution of VMs between two arrays doesn’t help, then you better combine two MDisks of each type in its own storage pool for striping between MDisks.

Same story for number of LUNs. IBM recommends one to one LUN to MDisk relationship. But read carefully. Recommendation comes from the fact that different workloads can clash and degrade array performance. But if we have generally the same I/O patterns coming to the array it’s safe to make several LUNs on it, until latency is in the acceptable range. Moreover, when it comes to vSphere and VMFS, it’s beneficial to have at least two volumes in terms of manageability. With several LUNs you will at least have an ability to move VMs between LUNs for reconfiguration purposes. Also keep in mind that ESXi 5 hypervisor limit each host to storage queue of depth 32 per LUN. It means that if you have one big LUN and many VMs running on the host, you can quickly reach queue limit. On the other hand do not create too many LUNs or you will oversubscribe storage processors (SPs).

Sample configuration

IBM recommends constructing both RAID 10 and RAID 5 arrays from 8 drives + 1 spare drive. But since we have 16 SAS and 10 NL-SAS I would launch CLI and create two arrays: one 14 drives + 2 spares RAID 10 and one 8 drives + 2 spares RAID 5 (or 9 drives + 1 spare, but it’s not a good idea to create RAID with uneven number of drives). Each RAID in its own pool. Several LUNs in each pool. I would go for 2TB LUNs.